3.1.92 \(\int \frac {x^3 (a+b \log (c x^n))^2}{d+e x} \, dx\) [92]

Optimal. Leaf size=271 \[ -\frac {2 a b d^2 n x}{e^3}+\frac {2 b^2 d^2 n^2 x}{e^3}-\frac {b^2 d n^2 x^2}{4 e^2}+\frac {2 b^2 n^2 x^3}{27 e}-\frac {2 b^2 d^2 n x \log \left (c x^n\right )}{e^3}+\frac {b d n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 b n x^3 \left (a+b \log \left (c x^n\right )\right )}{9 e}+\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {d x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}+\frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{3 e}-\frac {d^3 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}-\frac {2 b d^3 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}+\frac {2 b^2 d^3 n^2 \text {Li}_3\left (-\frac {e x}{d}\right )}{e^4} \]

[Out]

-2*a*b*d^2*n*x/e^3+2*b^2*d^2*n^2*x/e^3-1/4*b^2*d*n^2*x^2/e^2+2/27*b^2*n^2*x^3/e-2*b^2*d^2*n*x*ln(c*x^n)/e^3+1/
2*b*d*n*x^2*(a+b*ln(c*x^n))/e^2-2/9*b*n*x^3*(a+b*ln(c*x^n))/e+d^2*x*(a+b*ln(c*x^n))^2/e^3-1/2*d*x^2*(a+b*ln(c*
x^n))^2/e^2+1/3*x^3*(a+b*ln(c*x^n))^2/e-d^3*(a+b*ln(c*x^n))^2*ln(1+e*x/d)/e^4-2*b*d^3*n*(a+b*ln(c*x^n))*polylo
g(2,-e*x/d)/e^4+2*b^2*d^3*n^2*polylog(3,-e*x/d)/e^4

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Rubi [A]
time = 0.20, antiderivative size = 271, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 8, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {2395, 2333, 2332, 2342, 2341, 2354, 2421, 6724} \begin {gather*} -\frac {2 b d^3 n \text {PolyLog}\left (2,-\frac {e x}{d}\right ) \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 b^2 d^3 n^2 \text {PolyLog}\left (3,-\frac {e x}{d}\right )}{e^4}-\frac {d^3 \log \left (\frac {e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )^2}{e^4}+\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {d x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}+\frac {b d n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{3 e}-\frac {2 b n x^3 \left (a+b \log \left (c x^n\right )\right )}{9 e}-\frac {2 a b d^2 n x}{e^3}-\frac {2 b^2 d^2 n x \log \left (c x^n\right )}{e^3}+\frac {2 b^2 d^2 n^2 x}{e^3}-\frac {b^2 d n^2 x^2}{4 e^2}+\frac {2 b^2 n^2 x^3}{27 e} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^3*(a + b*Log[c*x^n])^2)/(d + e*x),x]

[Out]

(-2*a*b*d^2*n*x)/e^3 + (2*b^2*d^2*n^2*x)/e^3 - (b^2*d*n^2*x^2)/(4*e^2) + (2*b^2*n^2*x^3)/(27*e) - (2*b^2*d^2*n
*x*Log[c*x^n])/e^3 + (b*d*n*x^2*(a + b*Log[c*x^n]))/(2*e^2) - (2*b*n*x^3*(a + b*Log[c*x^n]))/(9*e) + (d^2*x*(a
+ b*Log[c*x^n])^2)/e^3 - (d*x^2*(a + b*Log[c*x^n])^2)/(2*e^2) + (x^3*(a + b*Log[c*x^n])^2)/(3*e) - (d^3*(a +
b*Log[c*x^n])^2*Log[1 + (e*x)/d])/e^4 - (2*b*d^3*n*(a + b*Log[c*x^n])*PolyLog[2, -((e*x)/d)])/e^4 + (2*b^2*d^3
*n^2*PolyLog[3, -((e*x)/d)])/e^4

Rule 2332

Int[Log[(c_.)*(x_)^(n_.)], x_Symbol] :> Simp[x*Log[c*x^n], x] - Simp[n*x, x] /; FreeQ[{c, n}, x]

Rule 2333

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b*Log[c*x^n])^p, x] - Dist[b*n*p, In
t[(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{a, b, c, n}, x] && GtQ[p, 0] && IntegerQ[2*p]

Rule 2341

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Log[c*x^
n])/(d*(m + 1))), x] - Simp[b*n*((d*x)^(m + 1)/(d*(m + 1)^2)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1
]

Rule 2342

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Lo
g[c*x^n])^p/(d*(m + 1))), x] - Dist[b*n*(p/(m + 1)), Int[(d*x)^m*(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{
a, b, c, d, m, n}, x] && NeQ[m, -1] && GtQ[p, 0]

Rule 2354

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[Log[1 + e*(x/d)]*((a +
b*Log[c*x^n])^p/e), x] - Dist[b*n*(p/e), Int[Log[1 + e*(x/d)]*((a + b*Log[c*x^n])^(p - 1)/x), x], x] /; FreeQ[
{a, b, c, d, e, n}, x] && IGtQ[p, 0]

Rule 2395

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^(r_.))^(q_.), x_Symbol]
:> With[{u = ExpandIntegrand[(a + b*Log[c*x^n])^p, (f*x)^m*(d + e*x^r)^q, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[
{a, b, c, d, e, f, m, n, p, q, r}, x] && IntegerQ[q] && (GtQ[q, 0] || (IGtQ[p, 0] && IntegerQ[m] && IntegerQ[r
]))

Rule 2421

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> Simp
[(-PolyLog[2, (-d)*f*x^m])*((a + b*Log[c*x^n])^p/m), x] + Dist[b*n*(p/m), Int[PolyLog[2, (-d)*f*x^m]*((a + b*L
og[c*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps

\begin {align*} \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{d+e x} \, dx &=\int \left (\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {d x \left (a+b \log \left (c x^n\right )\right )^2}{e^2}+\frac {x^2 \left (a+b \log \left (c x^n\right )\right )^2}{e}-\frac {d^3 \left (a+b \log \left (c x^n\right )\right )^2}{e^3 (d+e x)}\right ) \, dx\\ &=\frac {d^2 \int \left (a+b \log \left (c x^n\right )\right )^2 \, dx}{e^3}-\frac {d^3 \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{d+e x} \, dx}{e^3}-\frac {d \int x \left (a+b \log \left (c x^n\right )\right )^2 \, dx}{e^2}+\frac {\int x^2 \left (a+b \log \left (c x^n\right )\right )^2 \, dx}{e}\\ &=\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {d x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}+\frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{3 e}-\frac {d^3 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}+\frac {\left (2 b d^3 n\right ) \int \frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {e x}{d}\right )}{x} \, dx}{e^4}-\frac {\left (2 b d^2 n\right ) \int \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^3}+\frac {(b d n) \int x \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^2}-\frac {(2 b n) \int x^2 \left (a+b \log \left (c x^n\right )\right ) \, dx}{3 e}\\ &=-\frac {2 a b d^2 n x}{e^3}-\frac {b^2 d n^2 x^2}{4 e^2}+\frac {2 b^2 n^2 x^3}{27 e}+\frac {b d n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 b n x^3 \left (a+b \log \left (c x^n\right )\right )}{9 e}+\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {d x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}+\frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{3 e}-\frac {d^3 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}-\frac {2 b d^3 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}-\frac {\left (2 b^2 d^2 n\right ) \int \log \left (c x^n\right ) \, dx}{e^3}+\frac {\left (2 b^2 d^3 n^2\right ) \int \frac {\text {Li}_2\left (-\frac {e x}{d}\right )}{x} \, dx}{e^4}\\ &=-\frac {2 a b d^2 n x}{e^3}+\frac {2 b^2 d^2 n^2 x}{e^3}-\frac {b^2 d n^2 x^2}{4 e^2}+\frac {2 b^2 n^2 x^3}{27 e}-\frac {2 b^2 d^2 n x \log \left (c x^n\right )}{e^3}+\frac {b d n x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac {2 b n x^3 \left (a+b \log \left (c x^n\right )\right )}{9 e}+\frac {d^2 x \left (a+b \log \left (c x^n\right )\right )^2}{e^3}-\frac {d x^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 e^2}+\frac {x^3 \left (a+b \log \left (c x^n\right )\right )^2}{3 e}-\frac {d^3 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )}{e^4}-\frac {2 b d^3 n \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )}{e^4}+\frac {2 b^2 d^3 n^2 \text {Li}_3\left (-\frac {e x}{d}\right )}{e^4}\\ \end {align*}

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Mathematica [A]
time = 0.12, size = 211, normalized size = 0.78 \begin {gather*} -\frac {-108 d^2 e x \left (a+b \log \left (c x^n\right )\right )^2+54 d e^2 x^2 \left (a+b \log \left (c x^n\right )\right )^2-36 e^3 x^3 \left (a+b \log \left (c x^n\right )\right )^2+216 b d^2 e n x \left (a-b n+b \log \left (c x^n\right )\right )-8 b e^3 n x^3 \left (b n-3 \left (a+b \log \left (c x^n\right )\right )\right )+27 b d e^2 n x^2 \left (b n-2 \left (a+b \log \left (c x^n\right )\right )\right )+108 d^3 \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {e x}{d}\right )+216 b d^3 n \left (\left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right )-b n \text {Li}_3\left (-\frac {e x}{d}\right )\right )}{108 e^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^3*(a + b*Log[c*x^n])^2)/(d + e*x),x]

[Out]

-1/108*(-108*d^2*e*x*(a + b*Log[c*x^n])^2 + 54*d*e^2*x^2*(a + b*Log[c*x^n])^2 - 36*e^3*x^3*(a + b*Log[c*x^n])^
2 + 216*b*d^2*e*n*x*(a - b*n + b*Log[c*x^n]) - 8*b*e^3*n*x^3*(b*n - 3*(a + b*Log[c*x^n])) + 27*b*d*e^2*n*x^2*(
b*n - 2*(a + b*Log[c*x^n])) + 108*d^3*(a + b*Log[c*x^n])^2*Log[1 + (e*x)/d] + 216*b*d^3*n*((a + b*Log[c*x^n])*
PolyLog[2, -((e*x)/d)] - b*n*PolyLog[3, -((e*x)/d)]))/e^4

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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order 4.
time = 0.24, size = 4508, normalized size = 16.63

method	result	size
risch	\(\text {Expression too large to display}\)	\(4508\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a+b*ln(c*x^n))^2/(e*x+d),x,method=_RETURNVERBOSE)

[Out]

-1/4/e^2*d*x^2*Pi^2*b^2*csgn(I*c)*csgn(I*c*x^n)^5+1/3*a^2/e*x^3+a^2/e^3*x*d^2-a^2*d^3/e^4*ln(e*x+d)-1/2*a^2/e^
2*d*x^2-1/2*d^3/e^4*ln(e*x+d)*Pi^2*b^2*csgn(I*x^n)*csgn(I*c*x^n)^5+1/6/e*x^3*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)*
csgn(I*c*x^n)^3+I*d^3/e^4*ln(e*x+d)*Pi*a*b*csgn(I*c*x^n)^3+1/2/e^2*d*x^2*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)*csgn(I
*c*x^n)^4-1/4/e^3*x*d^2*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2+2/e^3*x*d^2*ln(c)*a*b-2*d^3/e^4*ln(
e*x+d)*ln(c)*a*b+2*n*d^3/e^4*dilog(-e*x/d)*b^2*ln(c)+1/2/e^2*n*d*x^2*b^2*ln(c)-2/e^3*n*x*d^2*b^2*ln(c)-1/e^2*d
*x^2*ln(c)*a*b-2/9*b/e*n*x^3*a+1/3*b^2*ln(x^n)^2/e*x^3-1/9*I/e*n*x^3*b^2*Pi*csgn(I*x^n)*csgn(I*c*x^n)^2-1/4*I/
e^2*n*d*x^2*b^2*Pi*csgn(I*c*x^n)^3+1/6/e*x^3*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)^2*csgn(I*c*x^n)^3+1/8/e^2*d*x^2*Pi
^2*b^2*csgn(I*c)^2*csgn(I*c*x^n)^4+1/2*b/e^2*n*d*x^2*a+2*b*n*d^3/e^4*dilog(-e*x/d)*a-1/3*I/e*x^3*ln(c)*Pi*b^2*
csgn(I*c*x^n)^3-1/3*I/e*x^3*Pi*a*b*csgn(I*c*x^n)^3+49/36*I*d^3/e^4*n*b^2*Pi*csgn(I*c*x^n)^3+1/2/e^3*x*d^2*Pi^2
*b^2*csgn(I*c)*csgn(I*c*x^n)^5-1/4/e^3*x*d^2*Pi^2*b^2*csgn(I*x^n)^2*csgn(I*c*x^n)^4-1/12/e*x^3*Pi^2*b^2*csgn(I
*c)^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2+2*b^2*n*d^3/e^4*ln(e*x+d)*ln(x^n)*ln(-e*x/d)+1/4*d^3/e^4*ln(e*x+d)*Pi^2*b^
2*csgn(I*c)^2*csgn(I*c*x^n)^4-1/2*d^3/e^4*ln(e*x+d)*Pi^2*b^2*csgn(I*c)*csgn(I*c*x^n)^5+1/4*d^3/e^4*ln(e*x+d)*P
i^2*b^2*csgn(I*x^n)^2*csgn(I*c*x^n)^4+1/9*I/e*n*x^3*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)+1/2*I/e^2*d*x^2
*Pi*a*b*csgn(I*c*x^n)^3-1/4/e^2*d*x^2*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)*csgn(I*c*x^n)^3-1/4/e^2*d*x^2*Pi^2*b^2*
csgn(I*c)*csgn(I*x^n)^2*csgn(I*c*x^n)^3-b^2*ln(x^n)^2*d^3/e^4*ln(e*x+d)-2/9*b^2*n/e*ln(x^n)*x^3+2/3*b/e*ln(x^n
)*x^3*a+I*d^3/e^4*ln(e*x+d)*ln(c)*Pi*b^2*csgn(I*c*x^n)^3+1/2/e^3*x*d^2*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)^2*csgn(I
*c*x^n)^3-49/18*b*d^3/e^4*n*a-I/e^3*ln(x^n)*x*d^2*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)-1/4*I/e^2*n*d*x^2
*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)-I*n*d^3/e^4*dilog(-e*x/d)*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^
n)-1/12/e*x^3*Pi^2*b^2*csgn(I*x^n)^2*csgn(I*c*x^n)^4+1/6/e*x^3*Pi^2*b^2*csgn(I*x^n)*csgn(I*c*x^n)^5+2/3/e*ln(x
^n)*x^3*b^2*ln(c)-2/9/e*n*x^3*b^2*ln(c)-49/18*d^3/e^4*n*b^2*ln(c)-d^3/e^4*ln(e*x+d)*ln(c)^2*b^2-1/2/e^2*d*x^2*
ln(c)^2*b^2+2/3/e*x^3*ln(c)*a*b+1/e^3*x*d^2*ln(c)^2*b^2+1/8/e^2*d*x^2*Pi^2*b^2*csgn(I*x^n)^2*csgn(I*c*x^n)^4-4
9/36*I*d^3/e^4*n*b^2*Pi*csgn(I*x^n)*csgn(I*c*x^n)^2-1/4/e^3*x*d^2*Pi^2*b^2*csgn(I*c*x^n)^6+1/4*d^3/e^4*ln(e*x+
d)*Pi^2*b^2*csgn(I*c*x^n)^6-1/12/e*x^3*Pi^2*b^2*csgn(I*c)^2*csgn(I*c*x^n)^4+1/6/e*x^3*Pi^2*b^2*csgn(I*c)*csgn(
I*c*x^n)^5-I*n*d^3/e^4*dilog(-e*x/d)*b^2*Pi*csgn(I*c*x^n)^3+1/3*I/e*ln(x^n)*x^3*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)
^2+1/3*I/e*x^3*ln(c)*Pi*b^2*csgn(I*x^n)*csgn(I*c*x^n)^2+1/9*I/e*n*x^3*b^2*Pi*csgn(I*c*x^n)^3-1/3*I/e*ln(x^n)*x
^3*b^2*Pi*csgn(I*c*x^n)^3+2*n*d^3/e^4*ln(e*x+d)*ln(-e*x/d)*b^2*ln(c)-I/e^3*n*x*d^2*b^2*Pi*csgn(I*c)*csgn(I*c*x
^n)^2-I*ln(x^n)*d^3/e^4*ln(e*x+d)*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2-1/4/e^3*x*d^2*Pi^2*b^2*csgn(I*c)^2*csgn(I*c
*x^n)^4+1/3*I/e*x^3*ln(c)*Pi*b^2*csgn(I*c)*csgn(I*c*x^n)^2-2*b^2*d^3/e^4*ln(x)*dilog(-e*x/d)*n^2+b^2*d^3/e^4*n
^2*ln(x)^2*ln(e*x+d)-b^2*d^3/e^4*n^2*ln(x)^2*ln(1+e*x/d)-2*b^2*d^3/e^4*n^2*ln(x)*polylog(2,-e*x/d)+b^2*ln(x^n)
^2/e^3*x*d^2-1/2*d^3/e^4*ln(e*x+d)*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)^2*csgn(I*c*x^n)^3+d^3/e^4*ln(e*x+d)*Pi^2*b^2
*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)^4-2*b^2*d^3/e^4*ln(x)*ln(e*x+d)*ln(-e*x/d)*n^2+2*b*n*d^3/e^4*ln(e*x+d)*ln
(-e*x/d)*a+1/3*I/e*x^3*Pi*a*b*csgn(I*c)*csgn(I*c*x^n)^2+1/3*I/e*x^3*Pi*a*b*csgn(I*x^n)*csgn(I*c*x^n)^2-1/4/e^2
*d*x^2*Pi^2*b^2*csgn(I*x^n)*csgn(I*c*x^n)^5-I/e^3*x*d^2*ln(c)*Pi*b^2*csgn(I*c*x^n)^3-I/e^3*x*d^2*Pi*a*b*csgn(I
*c*x^n)^3-I/e^3*x*d^2*ln(c)*Pi*b^2*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)-I/e^3*x*d^2*Pi*a*b*csgn(I*c)*csgn(I*x^n
)*csgn(I*c*x^n)+1/2*I/e^2*ln(x^n)*d*x^2*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)+1/2/e^3*x*d^2*Pi^2*b^2*csgn
(I*x^n)*csgn(I*c*x^n)^5-49/36*I*d^3/e^4*n*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2-I/e^3*ln(x^n)*x*d^2*b^2*Pi*csgn(I*c
*x^n)^3-1/9*I/e*n*x^3*b^2*Pi*csgn(I*c)*csgn(I*c*x^n)^2+1/2*I/e^2*ln(x^n)*d*x^2*b^2*Pi*csgn(I*c*x^n)^3+1/3/e*x^
3*ln(c)^2*b^2+1/3*I/e*ln(x^n)*x^3*b^2*Pi*csgn(I*x^n)*csgn(I*c*x^n)^2+1/2*I/e^2*d*x^2*ln(c)*Pi*b^2*csgn(I*c*x^n
)^3-1/e^3*x*d^2*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)^4+1/4*d^3/e^4*ln(e*x+d)*Pi^2*b^2*csgn(I*c)^2*csgn
(I*x^n)^2*csgn(I*c*x^n)^2+1/8/e^2*d*x^2*Pi^2*b^2*csgn(I*c)^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2-I*n*d^3/e^4*ln(e*x+
d)*ln(-e*x/d)*b^2*Pi*csgn(I*c)*csgn(I*x^n)*csgn(I*c*x^n)-2*a*b*d^2*n*x/e^3+1/2/e^3*x*d^2*Pi^2*b^2*csgn(I*c)^2*
csgn(I*x^n)*csgn(I*c*x^n)^3+2/27*b^2*n^2*x^3/e-2*ln(x^n)*d^3/e^4*ln(e*x+d)*b^2*ln(c)-b/e^2*ln(x^n)*d*x^2*a+2*b
/e^3*ln(x^n)*x*d^2*a-2*b*ln(x^n)*d^3/e^4*ln(e*x+d)*a+1/8/e^2*d*x^2*Pi^2*b^2*csgn(I*c*x^n)^6-1/e^2*ln(x^n)*d*x^
2*b^2*ln(c)+2/e^3*ln(x^n)*x*d^2*b^2*ln(c)+I/e^3*n*x*d^2*b^2*Pi*csgn(I*c*x^n)^3+I*ln(x^n)*d^3/e^4*ln(e*x+d)*b^2
*Pi*csgn(I*c*x^n)^3+1/2*b^2*n/e^2*ln(x^n)*d*x^2-2*b^2*n/e^3*ln(x^n)*x*d^2+2*b^2*n*d^3/e^4*ln(x^n)*dilog(-e*x/d
)-1/3/e*x^3*Pi^2*b^2*csgn(I*c)*csgn(I*x^n)*csgn...

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))^2/(e*x+d),x, algorithm="maxima")

[Out]

-1/6*(6*d^3*e^(-4)*log(x*e + d) - (2*x^3*e^2 - 3*d*x^2*e + 6*d^2*x)*e^(-3))*a^2 + integrate((b^2*x^3*log(x^n)^
2 + 2*(b^2*log(c) + a*b)*x^3*log(x^n) + (b^2*log(c)^2 + 2*a*b*log(c))*x^3)/(x*e + d), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))^2/(e*x+d),x, algorithm="fricas")

[Out]

integral((b^2*x^3*log(c*x^n)^2 + 2*a*b*x^3*log(c*x^n) + a^2*x^3)/(x*e + d), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3} \left (a + b \log {\left (c x^{n} \right )}\right )^{2}}{d + e x}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(a+b*ln(c*x**n))**2/(e*x+d),x)

[Out]

Integral(x**3*(a + b*log(c*x**n))**2/(d + e*x), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))^2/(e*x+d),x, algorithm="giac")

[Out]

integrate((b*log(c*x^n) + a)^2*x^3/(x*e + d), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^3\,{\left (a+b\,\ln \left (c\,x^n\right )\right )}^2}{d+e\,x} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^3*(a + b*log(c*x^n))^2)/(d + e*x),x)

[Out]

int((x^3*(a + b*log(c*x^n))^2)/(d + e*x), x)

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